Optimal. Leaf size=419 \[ \frac {\sqrt {b} \left (\frac {b x^2}{a}+1\right )^{3/4} \left (-21 a^2 d^2-76 a b c d+20 b^2 c^2\right ) \operatorname {EllipticF}\left (\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ),2\right )}{42 a^{3/2} c \left (a+b x^2\right )^{3/4} (b c-a d)^3}+\frac {b x \left (-21 a^2 d^2-76 a b c d+20 b^2 c^2\right )}{42 a^2 c \left (a+b x^2\right )^{3/4} (b c-a d)^3}+\frac {\sqrt [4]{a} d^2 \sqrt {-\frac {b x^2}{a}} (13 b c-2 a d) \Pi \left (-\frac {\sqrt {a} \sqrt {d}}{\sqrt {a d-b c}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c x (b c-a d)^4}+\frac {\sqrt [4]{a} d^2 \sqrt {-\frac {b x^2}{a}} (13 b c-2 a d) \Pi \left (\frac {\sqrt {a} \sqrt {d}}{\sqrt {a d-b c}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c x (b c-a d)^4}-\frac {d x}{2 c \left (a+b x^2\right )^{7/4} \left (c+d x^2\right ) (b c-a d)}+\frac {b x (7 a d+4 b c)}{14 a c \left (a+b x^2\right )^{7/4} (b c-a d)^2} \]
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Rubi [A] time = 0.48, antiderivative size = 419, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {414, 527, 530, 233, 231, 401, 108, 409, 1218} \[ \frac {b x \left (-21 a^2 d^2-76 a b c d+20 b^2 c^2\right )}{42 a^2 c \left (a+b x^2\right )^{3/4} (b c-a d)^3}+\frac {\sqrt {b} \left (\frac {b x^2}{a}+1\right )^{3/4} \left (-21 a^2 d^2-76 a b c d+20 b^2 c^2\right ) F\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{42 a^{3/2} c \left (a+b x^2\right )^{3/4} (b c-a d)^3}+\frac {\sqrt [4]{a} d^2 \sqrt {-\frac {b x^2}{a}} (13 b c-2 a d) \Pi \left (-\frac {\sqrt {a} \sqrt {d}}{\sqrt {a d-b c}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c x (b c-a d)^4}+\frac {\sqrt [4]{a} d^2 \sqrt {-\frac {b x^2}{a}} (13 b c-2 a d) \Pi \left (\frac {\sqrt {a} \sqrt {d}}{\sqrt {a d-b c}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{b x^2+a}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c x (b c-a d)^4}-\frac {d x}{2 c \left (a+b x^2\right )^{7/4} \left (c+d x^2\right ) (b c-a d)}+\frac {b x (7 a d+4 b c)}{14 a c \left (a+b x^2\right )^{7/4} (b c-a d)^2} \]
Antiderivative was successfully verified.
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Rule 108
Rule 231
Rule 233
Rule 401
Rule 409
Rule 414
Rule 527
Rule 530
Rule 1218
Rubi steps
\begin {align*} \int \frac {1}{\left (a+b x^2\right )^{11/4} \left (c+d x^2\right )^2} \, dx &=-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\int \frac {2 b c-a d-\frac {9}{2} b d x^2}{\left (a+b x^2\right )^{11/4} \left (c+d x^2\right )} \, dx}{2 c (b c-a d)}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}-\frac {\int \frac {\frac {1}{2} \left (-10 b^2 c^2+28 a b c d-7 a^2 d^2\right )-\frac {5}{4} b d (4 b c+7 a d) x^2}{\left (a+b x^2\right )^{7/4} \left (c+d x^2\right )} \, dx}{7 a c (b c-a d)^2}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {2 \int \frac {\frac {1}{4} \left (10 b^3 c^3-38 a b^2 c^2 d+126 a^2 b c d^2-21 a^3 d^3\right )+\frac {1}{8} b d \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x^2}{\left (a+b x^2\right )^{3/4} \left (c+d x^2\right )} \, dx}{21 a^2 c (b c-a d)^3}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\left (d^2 (13 b c-2 a d)\right ) \int \frac {1}{\left (a+b x^2\right )^{3/4} \left (c+d x^2\right )} \, dx}{4 c (b c-a d)^3}+\frac {\left (b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right )\right ) \int \frac {1}{\left (a+b x^2\right )^{3/4}} \, dx}{84 a^2 c (b c-a d)^3}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\left (d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-\frac {b x}{a}} (a+b x)^{3/4} (c+d x)} \, dx,x,x^2\right )}{8 c (b c-a d)^3 x}+\frac {\left (b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) \left (1+\frac {b x^2}{a}\right )^{3/4}\right ) \int \frac {1}{\left (1+\frac {b x^2}{a}\right )^{3/4}} \, dx}{84 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\sqrt {b} \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) \left (1+\frac {b x^2}{a}\right )^{3/4} F\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{42 a^{3/2} c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {\left (d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^4}{a}} \left (-b c+a d-d x^4\right )} \, dx,x,\sqrt [4]{a+b x^2}\right )}{2 c (b c-a d)^3 x}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\sqrt {b} \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) \left (1+\frac {b x^2}{a}\right )^{3/4} F\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{42 a^{3/2} c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}+\frac {\left (d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1-\frac {\sqrt {d} x^2}{\sqrt {-b c+a d}}\right ) \sqrt {1-\frac {x^4}{a}}} \, dx,x,\sqrt [4]{a+b x^2}\right )}{4 c (b c-a d)^4 x}+\frac {\left (d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1+\frac {\sqrt {d} x^2}{\sqrt {-b c+a d}}\right ) \sqrt {1-\frac {x^4}{a}}} \, dx,x,\sqrt [4]{a+b x^2}\right )}{4 c (b c-a d)^4 x}\\ &=\frac {b (4 b c+7 a d) x}{14 a c (b c-a d)^2 \left (a+b x^2\right )^{7/4}}+\frac {b \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) x}{42 a^2 c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}-\frac {d x}{2 c (b c-a d) \left (a+b x^2\right )^{7/4} \left (c+d x^2\right )}+\frac {\sqrt {b} \left (20 b^2 c^2-76 a b c d-21 a^2 d^2\right ) \left (1+\frac {b x^2}{a}\right )^{3/4} F\left (\left .\frac {1}{2} \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{42 a^{3/2} c (b c-a d)^3 \left (a+b x^2\right )^{3/4}}+\frac {\sqrt [4]{a} d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}} \Pi \left (-\frac {\sqrt {a} \sqrt {d}}{\sqrt {-b c+a d}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{a+b x^2}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c (b c-a d)^4 x}+\frac {\sqrt [4]{a} d^2 (13 b c-2 a d) \sqrt {-\frac {b x^2}{a}} \Pi \left (\frac {\sqrt {a} \sqrt {d}}{\sqrt {-b c+a d}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{a+b x^2}}{\sqrt [4]{a}}\right )\right |-1\right )}{4 c (b c-a d)^4 x}\\ \end {align*}
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Mathematica [C] time = 0.92, size = 550, normalized size = 1.31 \[ \frac {\frac {b d x^3 \left (\frac {b x^2}{a}+1\right )^{3/4} \left (21 a^2 d^2+76 a b c d-20 b^2 c^2\right ) F_1\left (\frac {3}{2};\frac {3}{4},1;\frac {5}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )}{(a d-b c)^3}+\frac {6 c \left (x^3 \left (21 a^4 d^3+42 a^3 b d^3 x^2+a^2 b^2 d \left (88 c^2+88 c d x^2+21 d^2 x^4\right )+4 a b^3 c \left (-8 c^2+11 c d x^2+19 d^2 x^4\right )-20 b^4 c^2 x^2 \left (c+d x^2\right )\right ) \left (4 a d F_1\left (\frac {3}{2};\frac {3}{4},2;\frac {5}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )+3 b c F_1\left (\frac {3}{2};\frac {7}{4},1;\frac {5}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )\right )-6 a c x \left (42 a^4 d^3+63 a^3 b d^2 \left (d x^2-2 c\right )+a^2 b^2 d \left (126 c^2-38 c d x^2+21 d^2 x^4\right )+2 a b^3 c \left (-21 c^2+41 c d x^2+38 d^2 x^4\right )-10 b^4 c^2 x^2 \left (3 c+2 d x^2\right )\right ) F_1\left (\frac {1}{2};\frac {3}{4},1;\frac {3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )\right )}{\left (a+b x^2\right ) \left (c+d x^2\right ) (b c-a d)^3 \left (6 a c F_1\left (\frac {1}{2};\frac {3}{4},1;\frac {3}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )-x^2 \left (4 a d F_1\left (\frac {3}{2};\frac {3}{4},2;\frac {5}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )+3 b c F_1\left (\frac {3}{2};\frac {7}{4},1;\frac {5}{2};-\frac {b x^2}{a},-\frac {d x^2}{c}\right )\right )\right )}}{252 a^2 c^2 \left (a+b x^2\right )^{3/4}} \]
Warning: Unable to verify antiderivative.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{2} + a\right )}^{\frac {11}{4}} {\left (d x^{2} + c\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.37, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {11}{4}} \left (d \,x^{2}+c \right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{2} + a\right )}^{\frac {11}{4}} {\left (d x^{2} + c\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{{\left (b\,x^2+a\right )}^{11/4}\,{\left (d\,x^2+c\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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